3.2.62 \(\int x (a+b x^2)^2 (c+d x^2)^3 \, dx\)

Optimal. Leaf size=71 \[ -\frac {b \left (c+d x^2\right )^5 (b c-a d)}{5 d^3}+\frac {\left (c+d x^2\right )^4 (b c-a d)^2}{8 d^3}+\frac {b^2 \left (c+d x^2\right )^6}{12 d^3} \]

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Rubi [A]  time = 0.12, antiderivative size = 71, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 20, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.100, Rules used = {444, 43} \begin {gather*} -\frac {b \left (c+d x^2\right )^5 (b c-a d)}{5 d^3}+\frac {\left (c+d x^2\right )^4 (b c-a d)^2}{8 d^3}+\frac {b^2 \left (c+d x^2\right )^6}{12 d^3} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[x*(a + b*x^2)^2*(c + d*x^2)^3,x]

[Out]

((b*c - a*d)^2*(c + d*x^2)^4)/(8*d^3) - (b*(b*c - a*d)*(c + d*x^2)^5)/(5*d^3) + (b^2*(c + d*x^2)^6)/(12*d^3)

Rule 43

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])

Rule 444

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_.)*((c_) + (d_.)*(x_)^(n_))^(q_.), x_Symbol] :> Dist[1/n, Subst[Int
[(a + b*x)^p*(c + d*x)^q, x], x, x^n], x] /; FreeQ[{a, b, c, d, m, n, p, q}, x] && NeQ[b*c - a*d, 0] && EqQ[m
- n + 1, 0]

Rubi steps

\begin {align*} \int x \left (a+b x^2\right )^2 \left (c+d x^2\right )^3 \, dx &=\frac {1}{2} \operatorname {Subst}\left (\int (a+b x)^2 (c+d x)^3 \, dx,x,x^2\right )\\ &=\frac {1}{2} \operatorname {Subst}\left (\int \left (\frac {(-b c+a d)^2 (c+d x)^3}{d^2}-\frac {2 b (b c-a d) (c+d x)^4}{d^2}+\frac {b^2 (c+d x)^5}{d^2}\right ) \, dx,x,x^2\right )\\ &=\frac {(b c-a d)^2 \left (c+d x^2\right )^4}{8 d^3}-\frac {b (b c-a d) \left (c+d x^2\right )^5}{5 d^3}+\frac {b^2 \left (c+d x^2\right )^6}{12 d^3}\\ \end {align*}

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Mathematica [A]  time = 0.03, size = 119, normalized size = 1.68 \begin {gather*} \frac {1}{120} x^2 \left (15 d x^6 \left (a^2 d^2+6 a b c d+3 b^2 c^2\right )+20 c x^4 \left (3 a^2 d^2+6 a b c d+b^2 c^2\right )+60 a^2 c^3+30 a c^2 x^2 (3 a d+2 b c)+12 b d^2 x^8 (2 a d+3 b c)+10 b^2 d^3 x^{10}\right ) \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[x*(a + b*x^2)^2*(c + d*x^2)^3,x]

[Out]

(x^2*(60*a^2*c^3 + 30*a*c^2*(2*b*c + 3*a*d)*x^2 + 20*c*(b^2*c^2 + 6*a*b*c*d + 3*a^2*d^2)*x^4 + 15*d*(3*b^2*c^2
 + 6*a*b*c*d + a^2*d^2)*x^6 + 12*b*d^2*(3*b*c + 2*a*d)*x^8 + 10*b^2*d^3*x^10))/120

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IntegrateAlgebraic [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int x \left (a+b x^2\right )^2 \left (c+d x^2\right )^3 \, dx \end {gather*}

Verification is not applicable to the result.

[In]

IntegrateAlgebraic[x*(a + b*x^2)^2*(c + d*x^2)^3,x]

[Out]

IntegrateAlgebraic[x*(a + b*x^2)^2*(c + d*x^2)^3, x]

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fricas [B]  time = 0.49, size = 134, normalized size = 1.89 \begin {gather*} \frac {1}{12} x^{12} d^{3} b^{2} + \frac {3}{10} x^{10} d^{2} c b^{2} + \frac {1}{5} x^{10} d^{3} b a + \frac {3}{8} x^{8} d c^{2} b^{2} + \frac {3}{4} x^{8} d^{2} c b a + \frac {1}{8} x^{8} d^{3} a^{2} + \frac {1}{6} x^{6} c^{3} b^{2} + x^{6} d c^{2} b a + \frac {1}{2} x^{6} d^{2} c a^{2} + \frac {1}{2} x^{4} c^{3} b a + \frac {3}{4} x^{4} d c^{2} a^{2} + \frac {1}{2} x^{2} c^{3} a^{2} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*(b*x^2+a)^2*(d*x^2+c)^3,x, algorithm="fricas")

[Out]

1/12*x^12*d^3*b^2 + 3/10*x^10*d^2*c*b^2 + 1/5*x^10*d^3*b*a + 3/8*x^8*d*c^2*b^2 + 3/4*x^8*d^2*c*b*a + 1/8*x^8*d
^3*a^2 + 1/6*x^6*c^3*b^2 + x^6*d*c^2*b*a + 1/2*x^6*d^2*c*a^2 + 1/2*x^4*c^3*b*a + 3/4*x^4*d*c^2*a^2 + 1/2*x^2*c
^3*a^2

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giac [B]  time = 0.32, size = 134, normalized size = 1.89 \begin {gather*} \frac {1}{12} \, b^{2} d^{3} x^{12} + \frac {3}{10} \, b^{2} c d^{2} x^{10} + \frac {1}{5} \, a b d^{3} x^{10} + \frac {3}{8} \, b^{2} c^{2} d x^{8} + \frac {3}{4} \, a b c d^{2} x^{8} + \frac {1}{8} \, a^{2} d^{3} x^{8} + \frac {1}{6} \, b^{2} c^{3} x^{6} + a b c^{2} d x^{6} + \frac {1}{2} \, a^{2} c d^{2} x^{6} + \frac {1}{2} \, a b c^{3} x^{4} + \frac {3}{4} \, a^{2} c^{2} d x^{4} + \frac {1}{2} \, a^{2} c^{3} x^{2} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*(b*x^2+a)^2*(d*x^2+c)^3,x, algorithm="giac")

[Out]

1/12*b^2*d^3*x^12 + 3/10*b^2*c*d^2*x^10 + 1/5*a*b*d^3*x^10 + 3/8*b^2*c^2*d*x^8 + 3/4*a*b*c*d^2*x^8 + 1/8*a^2*d
^3*x^8 + 1/6*b^2*c^3*x^6 + a*b*c^2*d*x^6 + 1/2*a^2*c*d^2*x^6 + 1/2*a*b*c^3*x^4 + 3/4*a^2*c^2*d*x^4 + 1/2*a^2*c
^3*x^2

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maple [A]  time = 0.00, size = 128, normalized size = 1.80 \begin {gather*} \frac {b^{2} d^{3} x^{12}}{12}+\frac {\left (2 a b \,d^{3}+3 b^{2} c \,d^{2}\right ) x^{10}}{10}+\frac {\left (a^{2} d^{3}+6 a b c \,d^{2}+3 b^{2} c^{2} d \right ) x^{8}}{8}+\frac {a^{2} c^{3} x^{2}}{2}+\frac {\left (3 a^{2} c \,d^{2}+6 a b \,c^{2} d +b^{2} c^{3}\right ) x^{6}}{6}+\frac {\left (3 a^{2} c^{2} d +2 a b \,c^{3}\right ) x^{4}}{4} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x*(b*x^2+a)^2*(d*x^2+c)^3,x)

[Out]

1/12*b^2*d^3*x^12+1/10*(2*a*b*d^3+3*b^2*c*d^2)*x^10+1/8*(a^2*d^3+6*a*b*c*d^2+3*b^2*c^2*d)*x^8+1/6*(3*a^2*c*d^2
+6*a*b*c^2*d+b^2*c^3)*x^6+1/4*(3*a^2*c^2*d+2*a*b*c^3)*x^4+1/2*a^2*c^3*x^2

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maxima [A]  time = 1.06, size = 127, normalized size = 1.79 \begin {gather*} \frac {1}{12} \, b^{2} d^{3} x^{12} + \frac {1}{10} \, {\left (3 \, b^{2} c d^{2} + 2 \, a b d^{3}\right )} x^{10} + \frac {1}{8} \, {\left (3 \, b^{2} c^{2} d + 6 \, a b c d^{2} + a^{2} d^{3}\right )} x^{8} + \frac {1}{2} \, a^{2} c^{3} x^{2} + \frac {1}{6} \, {\left (b^{2} c^{3} + 6 \, a b c^{2} d + 3 \, a^{2} c d^{2}\right )} x^{6} + \frac {1}{4} \, {\left (2 \, a b c^{3} + 3 \, a^{2} c^{2} d\right )} x^{4} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*(b*x^2+a)^2*(d*x^2+c)^3,x, algorithm="maxima")

[Out]

1/12*b^2*d^3*x^12 + 1/10*(3*b^2*c*d^2 + 2*a*b*d^3)*x^10 + 1/8*(3*b^2*c^2*d + 6*a*b*c*d^2 + a^2*d^3)*x^8 + 1/2*
a^2*c^3*x^2 + 1/6*(b^2*c^3 + 6*a*b*c^2*d + 3*a^2*c*d^2)*x^6 + 1/4*(2*a*b*c^3 + 3*a^2*c^2*d)*x^4

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mupad [B]  time = 0.04, size = 118, normalized size = 1.66 \begin {gather*} x^6\,\left (\frac {a^2\,c\,d^2}{2}+a\,b\,c^2\,d+\frac {b^2\,c^3}{6}\right )+x^8\,\left (\frac {a^2\,d^3}{8}+\frac {3\,a\,b\,c\,d^2}{4}+\frac {3\,b^2\,c^2\,d}{8}\right )+\frac {a^2\,c^3\,x^2}{2}+\frac {b^2\,d^3\,x^{12}}{12}+\frac {a\,c^2\,x^4\,\left (3\,a\,d+2\,b\,c\right )}{4}+\frac {b\,d^2\,x^{10}\,\left (2\,a\,d+3\,b\,c\right )}{10} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x*(a + b*x^2)^2*(c + d*x^2)^3,x)

[Out]

x^6*((b^2*c^3)/6 + (a^2*c*d^2)/2 + a*b*c^2*d) + x^8*((a^2*d^3)/8 + (3*b^2*c^2*d)/8 + (3*a*b*c*d^2)/4) + (a^2*c
^3*x^2)/2 + (b^2*d^3*x^12)/12 + (a*c^2*x^4*(3*a*d + 2*b*c))/4 + (b*d^2*x^10*(2*a*d + 3*b*c))/10

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sympy [B]  time = 0.09, size = 136, normalized size = 1.92 \begin {gather*} \frac {a^{2} c^{3} x^{2}}{2} + \frac {b^{2} d^{3} x^{12}}{12} + x^{10} \left (\frac {a b d^{3}}{5} + \frac {3 b^{2} c d^{2}}{10}\right ) + x^{8} \left (\frac {a^{2} d^{3}}{8} + \frac {3 a b c d^{2}}{4} + \frac {3 b^{2} c^{2} d}{8}\right ) + x^{6} \left (\frac {a^{2} c d^{2}}{2} + a b c^{2} d + \frac {b^{2} c^{3}}{6}\right ) + x^{4} \left (\frac {3 a^{2} c^{2} d}{4} + \frac {a b c^{3}}{2}\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*(b*x**2+a)**2*(d*x**2+c)**3,x)

[Out]

a**2*c**3*x**2/2 + b**2*d**3*x**12/12 + x**10*(a*b*d**3/5 + 3*b**2*c*d**2/10) + x**8*(a**2*d**3/8 + 3*a*b*c*d*
*2/4 + 3*b**2*c**2*d/8) + x**6*(a**2*c*d**2/2 + a*b*c**2*d + b**2*c**3/6) + x**4*(3*a**2*c**2*d/4 + a*b*c**3/2
)

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